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	<title>Comments on: Boolean algebra, my first experience.</title>
	<atom:link href="http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/feed/" rel="self" type="application/rss+xml" />
	<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/</link>
	<description>In Pursuit Of Truth and Beauty</description>
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		<title>By: Sanjeev</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-8912</link>
		<dc:creator>Sanjeev</dc:creator>
		<pubDate>Thu, 17 Sep 2009 09:52:52 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-8912</guid>
		<description>We must be careful when performing mathematical operations on sets rather than natural numbers. The similarties of properties is not present. The sameness which is present in the properties of addition and multiplication is not present. For example,  adding 2+2 gives the result 4, but multiplying 2*2 also gives 4. The same thing does not hold true when we consider another number 3. The results are 6, and 9 respectively which denote different quantities. The reasoning should be present to give correct answer. 

The same case obtains with the set thoery. There is an identify set which when multilpied retains the same result. Morevoer, the concepts of union, intersection etc partition the existing subsets. The logic of 1 or o are binary operations representing presence or absence of signal which is a result of an event taking place.</description>
		<content:encoded><![CDATA[<p>We must be careful when performing mathematical operations on sets rather than natural numbers. The similarties of properties is not present. The sameness which is present in the properties of addition and multiplication is not present. For example,  adding 2+2 gives the result 4, but multiplying 2*2 also gives 4. The same thing does not hold true when we consider another number 3. The results are 6, and 9 respectively which denote different quantities. The reasoning should be present to give correct answer. </p>
<p>The same case obtains with the set thoery. There is an identify set which when multilpied retains the same result. Morevoer, the concepts of union, intersection etc partition the existing subsets. The logic of 1 or o are binary operations representing presence or absence of signal which is a result of an event taking place.</p>
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		<title>By: vinay</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-4320</link>
		<dc:creator>vinay</dc:creator>
		<pubDate>Fri, 20 Mar 2009 06:00:08 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-4320</guid>
		<description>what is answer c+c`</description>
		<content:encoded><![CDATA[<p>what is answer c+c`</p>
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		<title>By: Idetrorce</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-45</link>
		<dc:creator>Idetrorce</dc:creator>
		<pubDate>Sat, 15 Dec 2007 23:21:13 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-45</guid>
		<description>very interesting, but I don&#039;t agree with you
Idetrorce</description>
		<content:encoded><![CDATA[<p>very interesting, but I don&#8217;t agree with you<br />
Idetrorce</p>
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		<title>By: sudharsh</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-44</link>
		<dc:creator>sudharsh</dc:creator>
		<pubDate>Sat, 08 Dec 2007 17:32:58 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-44</guid>
		<description>Hi, i guess both are right but you have to take into account the relation you operating on your operands..

1 R 1 = 0, where &#039;R&#039; is a XOR relation, or additon modulo 2 as edgarsr points out..
1 R 1 = 1, when &#039;R&#039; is a OR or a disjunctive relation...

I guess the choice of the symbol is the confusing aspect here, if you are choosing addition mod 2, you are better off choosing &#039;?&#039; instead of &#039;+&#039;..AFAIK thats the convention..</description>
		<content:encoded><![CDATA[<p>Hi, i guess both are right but you have to take into account the relation you operating on your operands..</p>
<p>1 R 1 = 0, where &#8216;R&#8217; is a XOR relation, or additon modulo 2 as edgarsr points out..<br />
1 R 1 = 1, when &#8216;R&#8217; is a OR or a disjunctive relation&#8230;</p>
<p>I guess the choice of the symbol is the confusing aspect here, if you are choosing addition mod 2, you are better off choosing &#8216;?&#8217; instead of &#8216;+&#8217;..AFAIK thats the convention..</p>
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		<title>By: sudharsh</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-46</link>
		<dc:creator>sudharsh</dc:creator>
		<pubDate>Sat, 08 Dec 2007 17:32:49 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-46</guid>
		<description>Hi, i guess both are right but you have to take into account the relation you operating on your operands..

1 R 1 = 0, where &#039;R&#039; is a XOR relation, or additon modulo 2 as edgarsr points out..
1 R 1 = 1, when &#039;R&#039; is a OR or a disjunctive relation...

I guess the choice of the symbol is the confusing aspect here, if you are choosing addition mod 2, you are better off choosing &#039;?&#039; instead of &#039;+&#039;..IMO thats the convention..</description>
		<content:encoded><![CDATA[<p>Hi, i guess both are right but you have to take into account the relation you operating on your operands..</p>
<p>1 R 1 = 0, where &#8216;R&#8217; is a XOR relation, or additon modulo 2 as edgarsr points out..<br />
1 R 1 = 1, when &#8216;R&#8217; is a OR or a disjunctive relation&#8230;</p>
<p>I guess the choice of the symbol is the confusing aspect here, if you are choosing addition mod 2, you are better off choosing &#8216;?&#8217; instead of &#8216;+&#8217;..IMO thats the convention..</p>
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		<title>By: edgarsr</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-48</link>
		<dc:creator>edgarsr</dc:creator>
		<pubDate>Sat, 08 Dec 2007 16:42:21 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-48</guid>
		<description>Well, the addition in Boolean algebra is not like that you mentinoed above, it is as follows:
0+0=0
0+1=1
1+0=1
1+1=0

It can be perceived as addition by module 2 (so, for example, when adding 1 and 1, you get 2, but 2 is equal to zero by module 2 (that is, you get zero remainder when dividing the sum by 2))</description>
		<content:encoded><![CDATA[<p>Well, the addition in Boolean algebra is not like that you mentinoed above, it is as follows:<br />
0+0=0<br />
0+1=1<br />
1+0=1<br />
1+1=0</p>
<p>It can be perceived as addition by module 2 (so, for example, when adding 1 and 1, you get 2, but 2 is equal to zero by module 2 (that is, you get zero remainder when dividing the sum by 2))</p>
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		<title>By: shriphani</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-47</link>
		<dc:creator>shriphani</dc:creator>
		<pubDate>Sat, 08 Dec 2007 02:39:26 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-47</guid>
		<description>Well the properties of addition in boolean algebras I suppose remain the same? I am not trying to state that union of sets = addition of numbers in boolean algebra. Do correct me if I am wrong.</description>
		<content:encoded><![CDATA[<p>Well the properties of addition in boolean algebras I suppose remain the same? I am not trying to state that union of sets = addition of numbers in boolean algebra. Do correct me if I am wrong.</p>
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		<title>By: edgarsr</title>
		<link>http://shriphani.com/blog/2007/12/07/boolean-algebra-my-first-experience/comment-page-1/#comment-49</link>
		<dc:creator>edgarsr</dc:creator>
		<pubDate>Sat, 08 Dec 2007 00:11:36 +0000</pubDate>
		<guid isPermaLink="false">http://shriphani.com/blog/?p=34#comment-49</guid>
		<description>I think you are misunderstanding some concepts here.. You assumed A, B and C to be sets, and then performed an addition operation with them. For example, A+A=A, because an addition here is just a union in fact. But then you came to the set {0, 1} and started to make the same operations (which you demonstrated on sets) with the individual elements of this particular set - with elements 0 and 1. This can&#039;t be done in this way - you can&#039;t do the same with elements, what you can do with sets.. So, for example, 1+1=0 in Boolean algebra, and it os not like it is with sets, when A+A=A..</description>
		<content:encoded><![CDATA[<p>I think you are misunderstanding some concepts here.. You assumed A, B and C to be sets, and then performed an addition operation with them. For example, A+A=A, because an addition here is just a union in fact. But then you came to the set {0, 1} and started to make the same operations (which you demonstrated on sets) with the individual elements of this particular set &#8211; with elements 0 and 1. This can&#8217;t be done in this way &#8211; you can&#8217;t do the same with elements, what you can do with sets.. So, for example, 1+1=0 in Boolean algebra, and it os not like it is with sets, when A+A=A..</p>
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